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You can introduce a block into a script without actually qualifying the block as being part of a subroutine or statement In this instance, the unqualified (or bare) block is interpreted in an identical fashion to a loop, except that the statements are executed only once Because an unqualified block acts as a loop, we can use the loop control statements (next, last, and redo) within the block, something that can t be done with if or unless, or the quasi-block statements of eval, sub (for subroutines), and do This operation can be useful for complex selections when you don t want to use multiple ifelse statements or complex logical comparisons For example, we could drop out of an if statement by enclosing the if BLOCK within an unqualified BLOCK so that the statements are identified as loop:

foreach ($exif as $section => $data) { foreach ($data as $key => $value) { echo "$section -> $key = $value\n"; } } echo "\n"; } } >

if (/valid/) { { last if /false/; print "Really valid!\n"; } }

This would skip the current input line from the file if there was a word next in the input line, while still allowing the remainder of the words from the file to be processed

5:

When line 8 is reached, how many objects are eligible for garbage collection A 4 B 5 C 6 D 8 E F 10 12

A more obvious example is the emulation of the Shellscript case statement, or the C/C++ switch statement The easiest solution is to use if statements embedded within a named block For example:

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SWITCH: { if ($date == $today) { print "Happy Birthday!\n"; last SWITCH; } if ($date != $today) { print "Happy Unbirthday!\n"; last SWITCH; } if ($date == $xmas) { print "Happy Christmas!\n"; last SWITCH; } }

This works because we can use the loop control operators last, next, and redo, which apply to the enclosing SWITCH block This also means you could write the same script as

Answer (for Objective 74): C is correct Because Stuff doesn t override equals(), there are five objects in the HashSet, plus the HashSet is also an object The int primitive associated with each Stuff object is not an object Note: Even if equals() was overridden, six objects would be eligible The duplicate Stuff object, while not in the Set, would still be eligible A, B, D, E, and F are incorrect based on the above

SWITCH: { print "Happy Birthday!\n", last SWITCH if ($date == $today); print "Happy Unbirthday!\n", last SWITCH if ($date != $today); print "Happy Christmas!\n", last SWITCH if ($date == $xmas); }

or for a more formatted solution that will appeal to C and Shellscript programmers:

SWITCH: { ($date == $today)

58 Given:

&& do { print "Happy Birthday!\n"; last SWITCH;

($date != $today)

}; && do { print "Happy Unbirthday!\n"; last SWITCH;

($date == $xmas)

1 public class Hose <E extends Hose> { 2 E innerE; 3 public static E doStuff(E e, Hose<E> e2) { 4 // insert code here 5 } 6 public E getE() { 7 return innerE; 8 } }

}; && do { print "Happy Christmas!\n"; last SWITCH; };

Note that in this last example, you could exclude the label The do {} blocks are not loops, and so the last command would ignore them and instead drop out of the parent SWITCH block Also note that because do is not strictly a statement, the block must be terminated by a semicolon

.

Which can be inserted, independently at line 4, for the code to compile (Choose all that apply) A return e; B return egetE(); C return e2; D return e2getE(); E F return new Hose()getE(); Compilation fails regardless of which return is inserted

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